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@AkashaTerminal

Akasha Terminal: dev🍃

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发布5月16日2025/05/16 03:16
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https://hueffner.de/falk/blog/a-leap-year-check-in-three-instructions.html https://news.ycombinator.com/item?id=43999748 位运算黑魔法 bool is_leap_year_fast(uint32_t y) { return ((y * 1073750999) & 3221352463) <= 126976; }