Как правильно проверить атрибуты доступа файла? То есть доступна ли запись в файл или является ли он исполняемым?
Для этого в Python есть функция os.access()
Проверять так:
os.access(path, flag)
Функция вернёт bool в зависимости от наличия указанного флага.
Всего есть 4 флага проверки:
os.F_OK - наличие файла на диске
os.R_OK - доступ на чтение
os.W_OK - доступ на запись
os.X_OK - доступ на исполнение
Например, вместо try-except лучше делать так (пример из документации):
if os.access("myfile", os.R_OK):
with open("myfile") as fp:
return fp.read()
#basic#libs
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☄️🌐We apologize for any inconvenience that may have been caused by the temporary disruption in service. We are committed to providing a seamless and secure experience for all of our users and appreciate your understanding during this time.
We are excited to introduce the bonus plan worth $10M as a token of gratitude for your patience and support. Details of the plan will be shared soon, and payouts will be processed next week. 👍❗️
Thank you once again for your trust in Wallet, and we look forward to continuing to provide you with a reliable and rewarding experience.🛡✨
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