Небольшой трик с регулярными выражениями который редко вижу в чужом коде.
Допустим, вам нужно распарсить простой текст и вытащить оттуда пары имя+телефон. Вернуть всё это надо в виде списка словарей. Возьмем очень простой пример текста.
>>> text = '''
>>> Alex:8999123456
>>> Mike:+799987654
>>> Oleg:+344456789
>>> '''
Соответственно, для выделения нужных элементов будем использовать группы. Получится такой паттерн:
(\w+):([\d+]+)
Как мы будем формировать словарь из найденных групп?
>>> import re
>>> results = []
>>> for match in re.finditer(r"(\w+):([\d+]+)", text):
>>> results.append({
>>> "name": match.group(1),
>>> "phone": match.group(2)
>>> })
>>> print(results)
[{'name': 'Alex', 'phone': '8999123456'}, ...]
Можно немного сократить запись используя zip
>>> results = []
>>> for match in re.finditer(r"(\w+):([\d+]+)", text):
>>> results.append(dict(zip(['name', 'phone'], match.groups())))
Но есть способ лучше! Это именованные группы в regex. Можно в паттерне указать имя группы и результат сразу забрать в виде словаря.
>>> for match in re.finditer(r"(?P<name>\w+):(?P<phone>[\d+]+)", text):
>>> results.append(match.groupdict())
То есть всё что я сделал, это добавил в начале группы (внутри сбокочек) такую запись:
(?P<group-name>...)
Теперь найденная группа имеет имя и можно обратиться к ней как к элементу списка
>>> name = match['name']
Либо забрать сразу весь словарь методом groupdict()
>>> match.groupdict()
#tricks#regex
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Strategy (prev. #MicroStrategy) has bought 22,337 $BTC for $1.57B at an average price of $70,194 per #Bitcoin.
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Strategy (prev. #MicroStrategy) has bought 17,994 $BTC for $1.28B at an average price of $70,946 per #Bitcoin.
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Strategy (prev. #MicroStrategy) has bought 3,015 $BTC for $204.1M at an average price of $67,700 per #Bitcoin.
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Strategy (prev. #MicroStrategy) has bought 2,486 $BTC for $168.4M at an average price of $67,710 per #Bitcoin.
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